Series.pow
Returns the exponential power of series and other, element-wise (binary operator pow).
danfo.Series.pow(other, options)
Parameters | Type | Description | Default |
|---|---|---|---|
other | Series|int| | values | |
options | Object | inplace: Boolean indicating whether to perform the operation inplace or not. Defaults to false | { inplace: false } |
Return: Series
Example
Exponential power with values of another series
Node
const dfd = require("danfojs-node")
let data1 = [2, 3, 4, 5]
let data2 = [1, 2, 3, 0]
let sf1 = new dfd.Series(data1)
let sf2 = new dfd.Series(data2)
sf1.pow(sf2).print()
Output
╔═══╤══════════════════════╗
║ │ 0 ║
╟───┼──────────────────────╢
║ 0 │ 2 ║
╟───┼──────────────────────╢
║ 1 │ 9 ║
╟───┼──────────────────────╢
║ 2 │ 64 ║
╟───┼──────────────────────╢
║ 3 │ 1 ║
╚═══╧══════════════════════╝
Exponential value with a value
Node
const dfd = require("danfojs-node")
let data1 = [1, 2, 3, 4, 5]
let sf1 = new dfd.Series(data1)
sf1.pow(2).print()
Output
╔═══╤══════════════════════╗
║ │ 0 ║
╟───┼──────────────────────╢
║ 0 │ 1 ║
╟───┼──────────────────────╢
║ 1 │ 4 ║
╟───┼──────────────────────╢
║ 2 │ 9 ║
╟───┼──────────────────────╢
║ 3 │ 16 ║
╟───┼──────────────────────╢
║ 4 │ 25 ║
╚═══╧══════════════════════╝
Last modified 1yr ago