Series.div
Return Floating division of series and other, element-wise (binary operator truediv).
danfo.Series.div(other, options)
Parameters | Type | Description | Default |
|---|---|---|---|
other | Series|int| | values | |
options | Object | inplace: Boolean indicating whether to perform the operation inplace or not. Defaults to false | { inplace: false } |
Return: Series
Example
divide with values of another series
Node
const dfd = require("danfojs-node")
let data1 = [30, 40, 3, 5]
let data2 = [1, 2, 3, 4]
let sf1 = new dfd.Series(data1)
let sf2 = new dfd.Series(data2)
sf1.div(sf2).print()
Output
╔═══╤══════════════════════╗
║ │ 0 ║
╟───┼──────────────────────╢
║ 0 │ 30 ║
╟───┼──────────────────────╢
║ 1 │ 20 ║
╟───┼──────────────────────╢
║ 2 │ 1 ║
╟───┼──────────────────────╢
║ 3 │ 1.25 ║
╚═══╧══════════════════════╝
Node
const dfd = require("danfojs-node")
let data1 = [1, 2, 3, 4, 5]
let sf1 = new dfd.Series(data1)
sf1.div(2).print()
Output
╔═══╤══════════════════════╗
║ │ 0 ║
╟───┼──────────────────────╢
║ 0 │ 0.5 ║
╟───┼──────────────────────╢
║ 1 │ 1 ║
╟───┼──────────────────────╢
║ 2 │ 1.5 ║
╟───┼──────────────────────╢
║ 3 │ 2 ║
╟───┼──────────────────────╢
║ 4 │ 2.5 ║
╚═══╧══════════════════════╝
Last modified 1yr ago