Series.div
Return Floating division of series and other, element-wise (binary operator truediv).
danfo.Series.div(other) [source]
Parameters | Type | Description | Default |
other | Series|int| | values | |
round | bool | specify if to round off the floating number | true |
Return: Series
Example
divide with values of another series
Node
Node
const dfd = require("danfojs-node")let data1 = [30, 40, 3, 5]let data2 = [1, 2, 3, 4]let sf1 = new dfd.Series(data1)let sf2 = new dfd.Series(data2)sf1.div(sf2).print()
Output
Output
╔═══╤══════════════════════╗║ │ 0 ║╟───┼──────────────────────╢║ 0 │ 30 ║╟───┼──────────────────────╢║ 1 │ 20 ║╟───┼──────────────────────╢║ 2 │ 1 ║╟───┼──────────────────────╢║ 3 │ 1.25 ║╚═══╧══════════════════════╝
divide with a value
Node
Node
const dfd = require("danfojs-node")let data1 = [1, 2, 3, 4, 5]let sf1 = new dfd.Series(data1)sf1.div(2).print()
Output
Output
╔═══╤══════════════════════╗║ │ 0 ║╟───┼──────────────────────╢║ 0 │ 0.5 ║╟───┼──────────────────────╢║ 1 │ 1 ║╟───┼──────────────────────╢║ 2 │ 1.5 ║╟───┼──────────────────────╢║ 3 │ 2 ║╟───┼──────────────────────╢║ 4 │ 2.5 ║╚═══╧══════════════════════╝
Last updated 3 months ago